How do you find the fourth derivative of $cos x$ $cos x$ ?

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Answer 1 · 2017-01-04T04:56:18

$cos x$ $cosx$

$\frac{d}{d x} cos x = - sin x$ $d/(dx)cosx=-sinx$

$\frac{d}{d x} (- sin x) = - cos x$ $d/(dx)(-sinx)=-cosx$

$\frac{d}{d x} (- cos x) = sin x$ $d/(dx)(-cosx)=sinx$

$\frac{d}{d x} (sin x) = cos x$ $d/(dx)(sinx)=cosx$

The fourth derivative of $cos x$ $cosx$ is $cos x$ $cosx$ .

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