How do you find the GCF of $21ab, 35a, 56ab^3$ ?

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Answer 1 · 2017-03-14T17:20:23

$7a$

$21 ab, 35 a, 56 ab^3$

divided by $a$
$21 b, 35, 56 b^3$

divided by $7$
$3 b, 5, 8 b^3$

since no more can be divided to the above expressions or number,
therefore it GCF is $a*7 = 7a$

How do you find the GCF of 21ab, 35a, 56ab^321ab, 35a, 56ab^3?