How do you find the GCF of $25 x^{3}, 45 x^{4}, 65 x^{2}$ $25x^3, 45x^4, 65x^2$ ?

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How do you find the GCF of $25 x^{3}, 45 x^{4}, 65 x^{2}$ $25x^3, 45x^4, 65x^2$ ?

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Answer 1 · 2018-05-26T02:35:53

$2925 x^{4}$ $2925x^4$

Explanation:

Find the factors of each first.
$25 x^{3} = 5^{2} \cdot x^{3}$ $25x^3=5^2*x^3$
$45 x^{4} = 3^{2} \cdot 5 \cdot x^{4}$ $45x^4=3^2*5*x^4$
$65 x^{2} = 5 \cdot 13 \cdot x^{2}$ $65x^2=5*13*x^2$

Use this to find the prime factorization of the GCF.
$3^{2} \cdot 5^{2} \cdot 13 \cdot x^{4}$ $3^2*5^2*13*x^4$

Solve.
$3^{2} \cdot 5^{2} \cdot 13 \cdot x^{4} = 2925 x^{4}$ $3^2*5^2*13*x^4=2925x^4$

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How do you find the GCF of $25 x^{3}, 45 x^{4}, 65 x^{2}$ $25x^3, 45x^4, 65x^2$ ?

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Explanation:

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How do you find the GCF of $25 x^{3}, 45 x^{4}, 65 x^{2}$ $25x^3, 45x^4, 65x^2$ ?