How do you find the gcf of $3 a^{3} - 6 a^{2} - 9 a$ $3a^3 - 6a^2 - 9a$ ?

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Answer 1 · 2015-07-08T02:40:50

Find the largest number and highest degree of $a$ $a$ that will divide evenly into all three terms in the equation. Multiply them to get the GCF.

$3 a^{3} - 6 a^{2} - 9 a$ $3a^3-6a^2-9a$

The greatest number that can be divided evenly into $3 a^{3},$ $3a^3,$ $- 6 a^{2},$ $-6a^2,$ and $- 9 a$ $-9a$ is $3$ $3$ .

The highest degree of $a$ $a$ that can be divided evenly into $3 a^{3},$ $3a^3,$ $- 6 a^{2},$ $-6a^2,$ a $- 9 a$ $-9a$ is $a$ $a$ .

The GCF for the equation is $3 \cdot a = 3 a$ $3*a=3a$ .

How do you find the gcf of 3a3−6a2−9a3a^3 - 6a^2 - 9a?