Question

How do you find the indefinite integral of `int 1/sqrt(x+1)`?

Answer 1

Let `u = x + 1`. Then `du = dx`.

`=int 1/sqrt(u)du`

`= int u^(-1/2) du`

`=2u^(1/2) + C`

`=2sqrt(x + 1) + C`

Hopefully this helps!