Question

How do you find the indefinite integral of `int 1/(x-5)`?

Answer 1

`int1/(x-5)dx=ln|(x-5)|+C`

Explanation:

`int(f'(x))/(f(x))dx=ln|f(x)|+C`

`int1/(x-5)dx`

`x!=5`

`d/(dx)(x-5)=1`

`int1/(x-5)dx=ln|(x-5)|+C`