How do you find the inflection points of the graph of the function: f(x) = ((4 x)/e^(9 x))?

1 Answer
Jul 29, 2015

Inflection points are points on the graph at which the concavity changes. So investigate concavity.

Explanation:

To investigate concavity, we will look at the sign of the second derivative.

f(x) = (4x)/e^(9x)

f'(x) = (4e^(9x) - 4xe^(9x)*9)/e^(18x)

= (4-36x)/e^(9x)

f''(x) = ((-36)e^(9x) - (4-36x)e^(9x)*9)/e^(18x)

= (36(9x-2))/e^(9x)

The factors 36 and e^(9x) are always positive, so the sign of f'' is the same as the sign of 9x-2 which changes at x=2/9

The point (2/9, f(2/9)) is the only inflection point.

Since f(2/9) = 8/(9e^2),

the inflection point is: (2/9, 8/(9e^2))