Question

How do you find the inverse of `f(x)=-(1/3)^x`?

Answer 1

x = `-log(-f(x))/log 3`

Explanation:

Here f(x) < 0 for all x.

`f(x) =-3^(-x)`.

So, `log (-f(x))=-x log 3`.
x = `-log(-f(x))/log 3`