How do you find the inverse of h(x)= x^3 - 3x^2 + 3x - 1 and is it a function?

1 Answer
Nov 30, 2016

The inverse of y = h(x) is x = y^(1/3)+1. The graphs of both are the same.

Explanation:

y = h(x)=(x-1)^3. So, #x-1 = y^(1/3). And so, the inverse is

x = h^(-1)(y) = y^(1/3)+1.

Both graphs are the same. This is a verification for exactitude, using the Socratic

graphics facility.

graph{y-(x-1)^3=0 [-10, 10, -5, 5]}

graph{x-1-y^(1/3)=0 [-10, 10, -5, 5]}

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