Question

How do you find the inverse of `y=log_7 49^x`?

Answer 1

Solved

Explanation:

`log_a b^x = xlog_a b`
`y = log_7 49^x`
Using the fact that `7^2=49`
`= log_7 7^(2x)`
`y=2xlog_7 7`
`y = 2x`