How do you find the length and direction of vector $2 - 4 i$ $2 - 4i$ ?

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Answer 1 · 2018-07-03T04:13:22

Length of the vector $2 - 4 i$ $2-4i$

$= \sqrt{2^{2} + {(- 4)}^{2}}$ $=\sqrt{2^2+(-4)^2}$

$= 2 \sqrt{5}$ $=2\sqrt5$

And the angle $θ$ $\theta$ in CCW with the positive x-axis

$θ = - {tan}^{- 1} ∣ ∣ ∣ - \frac{4}{2} ∣ ∣ ∣$ $\theta=-\tan^{-1}|-4/2|$

$= - {tan}^{- 1} (2)$ $=-\tan^{-1}(2)$

$= - {63.435}^{\circ}$ $=-63.435^\circ$

How do you find the length and direction of vector 2 - 4i2−4i2 - 4i?