How do you find the most general antiderivative of the function #f(x) = x(8 - x)^2#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Jim H Apr 11, 2015 #f(x) = x(8 - x)^2# multiply it out to get standard form for a polynomial, then antidifferentiate term by term. #f(x) = x(8 - x)^2 = x(64-16x+x^2) = x^3 - 16x^2+ 64x# Whose antiderivative is: #1/4 x^4 - 16/3 x^3 +32 x^2 + C# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 6070 views around the world You can reuse this answer Creative Commons License