How do you find the polar coordinates given #(1,-1)#?

1 Answer
Aug 29, 2016

#(1,-1)to(sqrt2,-pi/4)#

Explanation:

To convert from #color(blue)"cartesian to polar coordinates"#

That is #(x,y)to(r,theta)#

#color(orange)"Reminder"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(r=sqrt(x^2+y^2))color(white)(a/a)|)))" and " color(red)(|bar(ul(color(white)(a/a)color(black)(theta=tan^-1(y/x))color(white)(a/a)|)))#

here x = 1 and y = -1

#rArrr=sqrt(1^2+(-1)^2)=sqrt2#

Now, (1 ,-1) is in the 4th quadrant so we must ensure that #theta# is in the 4th quadrant.

#theta=tan^-1(-1)=-pi/4" in 4th quadrant"#

#rArr(1,-1)to(sqrt2,-pi/4)#