How do you find the polar coordinates given #(sqrt3, 1)#?

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Answer 1 · 2017-02-09T15:38:39

The answer is #=(2,pi/6)#

To convert from cartesian coordinates #(x,y)# to polar coordinates #(r,theta)#, we use the following equations

#r^2=x^2+y^2#

#theta=arctan(y/x)#

Here, we have

#(x,y)=(sqrt3,1)#

#r^2=(sqrt3)^2+1=4#

#r=2#

#theta=arctan(1/sqrt3)=arctan(sqrt3/3)#

#theta=pi/6#

So,

the polar coordinates are #(2,pi/6)#