How do you find the positive values of p for which #Sigma n/(1+n^2)^p# from #[2,oo)# converges?
1 Answer
Jul 20, 2017
The series:
is convergent for
Explanation:
Consider the series:
Based on the
Using this series for the limit comparison test:
which means that the two series have the same character. Then also the first series is convergent for