How do you find the product #-12*3#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer sjc · EZ as pi Dec 29, 2016 #-36# Explanation: #12.(-3)# #=12xx(-3)# firstly multiply the numbers ignoring the signs #12xx3=36# put a #+ or- #sign in according to the scheme. #+xx+ =+# #- xx - =+# #- xx + =-# #+ xx - =-# in this case we have only one #" "-" "# #:.12.(-3)=-36# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 3129 views around the world You can reuse this answer Creative Commons License