How do you find the product of $3p^4(4p^4+7p^3+4p+1)$ ?

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Answer 1 · 2016-11-30T03:10:57

$12p^8 + 21p^7 + 12p^5 + 3p^4$

Multiply $3p^4$ by each term in parenthesis:

$(3p^4*4p^4) + (3p^4*7p^3) + (3p^4*4p) + (3p^4*1) ->$

$(3p^4*4p^4) + (3p^4*7p^3) + (3p^4*4p^1) + (3p^4*1) ->$

Then multiply the numbers and the $x$ terms using the rules for exponents:

$12p^(4+4) + 21p^(4+3) + 12p^(4+1) + 3p^4 ->$

$12p^8 + 21p^7 + 12p^5 + 3p^4$

How do you find the product of 3p^4(4p^4+7p^3+4p+1)3p^4(4p^4+7p^3+4p+1)?