How do you find the product of #3p^4(4p^4+7p^3+4p+1)#? Algebra Polynomials and Factoring Multiplication of Monomials by Polynomials 1 Answer smendyka Nov 30, 2016 #12p^8 + 21p^7 + 12p^5 + 3p^4# Explanation: Multiply #3p^4# by each term in parenthesis: #(3p^4*4p^4) + (3p^4*7p^3) + (3p^4*4p) + (3p^4*1) -># #(3p^4*4p^4) + (3p^4*7p^3) + (3p^4*4p^1) + (3p^4*1) -># Then multiply the numbers and the #x# terms using the rules for exponents: #12p^(4+4) + 21p^(4+3) + 12p^(4+1) + 3p^4 -># #12p^8 + 21p^7 + 12p^5 + 3p^4# Answer link Related questions What is Multiplication of Monomials by Polynomials? How do you multiply monomials by polynomials? How do you multiply monomials by monomials? How do you multiply #(3xy^5)(-6x^4y^2)#? How do you multiply and simplify #6ab(-10a^2 b^3+c^5)#? How do you simplify #-3a^2b(9a^2-4b^2)#? How do you multiply #y(xy^4)#? How do you multiply #(2x-1)(x^3-2x^2+3x-4)#? How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#? How do you simplify #2t^2+(3+5)(4t)#? See all questions in Multiplication of Monomials by Polynomials Impact of this question 2139 views around the world You can reuse this answer Creative Commons License