How do you find the quotient of #-60div(-6)#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer Barney V. Jan 7, 2017 The quotient = 10 Explanation: #-60-:(-6)# #=-60/(-6/1)# #=-60 xx -1/6# #=60/6# #= 10# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 3451 views around the world You can reuse this answer Creative Commons License