How do you find the quotient of (x^3-43x+42) divided by (x^2+6x-7)?

Question

How do you find the quotient of (x^3-43x+42) divided by (x^2+6x-7)?

1 Answer

Impact of this question

1888 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-17T09:08:41

$x - 6$ $x-6$

Explanation:

$factorise numerator/denominator$ $"factorise numerator/denominator"$

$x^{3} - 43 x + 42$ $x^3-43x+42$

$= x^{2} (x - 1) + x (x - 1) - 42 (x - 1)$ $=x^2(x-1)+x(x-1)-42(x-1)$

$= (x - 1) (x^{2} + x - 42) = (x - 1) (x + 7) (x - 6)$ $=(x-1)(x^2+x-42)=(x-1)(x+7)(x-6)$

$x^{2} + 6 x + 7 = (x + 7) (x - 1)$ $x^2+6x+7=(x+7)(x-1)$

$\Rightarrow \frac{x^{3} - 43 x + 42}{x^{2} + 6 x - 7}$ $rArr(x^3-43x+42)/(x^2+6x-7)$

$=(cancel((x-1))cancel((x+7))(x-6))/(cancel((x+7))cancel((x-1)))=x-6$

Science

Math

Humanities

... and beyond

How do you find the quotient of (x^3-43x+42) divided by (x^2+6x-7)?

1 Answer

Explanation:

Related questions

Impact of this question