How do you find the radius of the circle whose equation is $(x - 3)² + (y + 1)² = 16$ ?

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Answer 1 · 2016-01-19T19:11:57

The equation of the circle standard form is:
$(x-h)^2 + (y-k)^2 = r^2$
from this the radius of the circle
$r = sqrt(r^2); r = sqrt16 = 4$

How do you find the radius of the circle whose equation is (x - 3)² + (y + 1)² = 16(x - 3)² + (y + 1)² = 16?