How do you find the range and domain of $(\frac{1}{2}) (arctan x)$ $(1/2)(arctan x)$ ?

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Answer 1 · 2018-04-11T12:09:03

Domain : $x ∣ (- \infty, \infty)$ $x|(-oo,oo)$
Range: $f (x) ∣ (- \frac{π}{4}, \frac{π}{4})$ $f(x)|(-pi/4,pi/4)$

$f (x) = \frac{1}{2} \cdot {tan}^{- 1} x$ $f(x)=1/2*tan^-1 x$

Domain of ${tan}^{- 1} x$ $tan^-1 x$ is any real value i.e $x ∣ (- \infty, \infty)$ $x|(-oo,oo)$

Range of ${tan}^{- 1} x$ $tan^-1 x$ is $f (x) ∣ (- \frac{π}{2}, \frac{π}{2})$ $f(x)|(-pi/2,pi/2)$

Domain of $(\frac{1}{2}) {tan}^{- 1} x$ $(1/2)tan^-1 x$ is $x ∣ (- \infty, \infty)$ $x|(-oo,oo)$

Range of $(\frac{1}{2}) {tan}^{- 1} x$ $(1/2)tan^-1 x$ is $f (x) ∣ (- \frac{π}{4}, \frac{π}{4})$ $f(x)|(-pi/4,pi/4)$

graph{1/2*arctan(x) [-10, 10, -5, 5]} [Ans]

How do you find the range and domain of (12)(arctanx) (1/2)(arctan x)?