How do you find the real solutions of the polynomial 9x2+5x3=6x4?

1 Answer
Jim G.
Jun 10, 2017

x=0,x≈−0.88,x≈1.71

Explanation:

rearrange the polynomial, equating to zero

⇒6x4−5x3−9x2=0

⇒x2(6x2−5x−9)=0← common factor

factor 6x2−5x−9 using the quadratic formula

with a=6,b=−5 and c=−9

x=5±√25+21612=5±√24112

⇒x≈1.71 or x≈−0.88orx=0

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