Question

How do you find the rectangular coordinate of `(-4, pi/3)`?

Answer 1

`pi/3` is in quadrant I. However, the negative value for the magnitude places the coordinate into quadrant III

Explanation:

`x = -4cos(pi/3)=-4(1/2)=-2`
`y=-4sin(pi/3)=-4(sqrt3/2)=-2sqrt3`

rectangular coordinate `=(-2,-2sqrt3)`

hope that helped