How do you find the slope of the tangent line to the graph of the function $f (x) = \frac{3}{2} x + 1$ $f(x)=3/2x+1$ at (-2,-2)?

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How do you find the slope of the tangent line to the graph of the function $f (x) = \frac{3}{2} x + 1$ $f(x)=3/2x+1$ at (-2,-2)?

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Answer 1 · 2016-11-19T01:36:58

$m = \frac{3}{2}$ $m=3/2$

Explanation:

$f (x) = \frac{3}{2} x + 1$ $f(x) = 3/2x + 1$ is a straight line, comparing with $y = m x + c$ $y=mx+c$ we see $m = \frac{3}{2}$ $m=3/2$ , so the gradient of the tangent line is $\frac{3}{2}$ $3/2$ everywhere.

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How do you find the slope of the tangent line to the graph of the function $f (x) = \frac{3}{2} x + 1$ $f(x)=3/2x+1$ at (-2,-2)?

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Explanation:

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How do you find the slope of the tangent line to the graph of the function $f (x) = \frac{3}{2} x + 1$ $f(x)=3/2x+1$ at (-2,-2)?