How do you find the sum or difference of $(2 x + 3 x^{2}) - (7 - 8 x^{2})$ $(2x+3x^2)-(7-8x^2)$ ?

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How do you find the sum or difference of $(2 x + 3 x^{2}) - (7 - 8 x^{2})$ $(2x+3x^2)-(7-8x^2)$ ?

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Answer 1 · 2017-07-23T10:28:30

$11 x^{2} + 2 x - 7$ $11x^2+2x-7$

Explanation:

$(2 x + 3 x^{2}) - (7 - 8 x^{2})$ $(2x+3x^2)-(7-8x^2)$

$(2 x + 3 x^{2}) + [- 1 \cdot (7 - 8 x^{2})]$ $(2x+3x^2)+[-1\cdot(7-8x^2)]$
$(2 x + 3 x^{2}) + [- 1 (7) + (- 1) (- 8 x^{2})]$ $(2x+3x^2)+[-1(7)+(-1)(-8x^2)]$ apply distributive property to second half
$(2 x + 3 x^{2}) + [- 7 + 8 x^{2}]$ $(2x+3x^2)+[-7+8x^2]$ simplify
$2 x + 3 x^{2} - 7 + 8 x^{2}$ $2x+3x^2-7+8x^2$ remove parentheses and change signs where needed
$2 x + 11 x^{2} - 7$ $2x+11x^2-7$ add like terms
$11 x^{2} + 2 x - 7$ $11x^2+2x-7$ reorder to quadratic format

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How do you find the sum or difference of $(2 x + 3 x^{2}) - (7 - 8 x^{2})$ $(2x+3x^2)-(7-8x^2)$ ?

1 Answer

Explanation:

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How do you find the sum or difference of (2x+3x2)−(7−8x2)(2x+3x^2)-(7-8x^2)?

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How do you find the sum or difference of $(2 x + 3 x^{2}) - (7 - 8 x^{2})$ $(2x+3x^2)-(7-8x^2)$ ?