How do you find the sum or difference of #(-8xy+3x^2-5y)+(4x^2-2y+6xy)#?

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Answer 1 · 2017-02-27T14:30:56

See the entire solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of the individual terms correctly:

#(-8xy + 3x^2 - 5y) + (4x^2 - 2y + 6xy)# becomes:

#-8xy + 3x^2 - 5y + 4x^2 - 2y + 6xy#

Next, group like terms:

#3x^2 + 4x^2 + 6xy - 8xy - 5y - 2y#

Now, combine like terms:

#(3 + 4)x^2 + (6 - 8)xy + (-5 - 2)y#

#7x^2 - 2xy - 7y#