Question

How do you find the sum or difference of `(a^3-3a^2+4)-(4a^2+7)`?

Answer 1

`a^3-7a^2-3`

Explanation:

You need to remove the brackets.

`(a^3 -3a^2+4)-(4a^2+7)`

`=a^3 -3a^2+4-4a^2-7`

`a^3-7a^2-3`