How do you find the value of the permutation P(4,2)?

1 Answer
May 25, 2018

12

Explanation:

"using the definition"

•color(white)(x)^nP_r=(n!)/((n-r)!)

"where "n! =n(n-1)(n-2)xx... xx3xx2xx1

color(white)(x)^4P_2=(4!)/((4-2)!)=(4!)/(2!)

color(white)(xxxxxxxxxx)=(4xx3xxcancel(color(red)(2xx1)))/cancel(color(red)(2xx1))=4xx3=12