How do you find the vertex and intercepts for (y1)2=4x?

1 Answer
Jul 2, 2017

Vertex is at (0,1), x-intercept is at (14,0) , y-intercept is at (0,1).

Explanation:

(y1)2=4xor(y1)2=4(x0).

This is parabola opening right. Comparing with standard equation of

(yk)2=4a(xh);(h,k) being vertex , we get here h=0,k=1.

So vertex is at (0,1) . Putting x=0 in the equation ,we can find

y-intercept as (y1)2=40or(y1)2=0ory1=0ory=1

So y-intercept is at y=1or(0,1). Putting y=0 in the equation,

we can find x-intercept as (01)2=4xor4x=1orx=14

So x-intercept is at x=14or(14,0)

graph{(y-1)^2=4x [-20, 20, -10, 10]}
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