Question

How do you find the vertex for `y = 2x^2 + 8x -3`?

Answer 1

Your quadratic is in the form `y=ax^2+bx+c` where:
`a=2`
`b=8`
`c=-3`
The coordinates of the vertex are:
`x_v=-b/(2a)`
`y_v=-Delta/(4a)`
Where `Delta=b^2-4ac`