How do you find the vertex of a parabola $f (x) = \frac{1}{4} {(x + 2)}^{2} - 9$ $f(x)=1/4(x+2)^2-9$ ?

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Answer 1 · 2015-08-01T13:09:50

Vertex of f(x) = (x + 2)^2/4 - 9.

Ans: Vertex (-2, -9)

The function is in vertex form
Vertex: x = -2 and y = -9

How do you find the vertex of a parabola f(x)=14(x+2)2−9f(x)=1/4(x+2)^2-9?