Question

How do you find the vertex of a parabola `y=[x-3]^2+10`?

Answer 1

The vertex of `y=[x-3]^2+10` is at `(3,10)`

Explanation:

Any parabolic equation of the form
`color(white)("XXXX")` `y=(x-a)^2+b`
is in "vertex form" with a vertex at `(a,b)`