How do you find the vertex of #f(x)=3(x-9)^2+4#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Meave60 Jul 17, 2015 The vertex is #(9, 4)#. Explanation: #f(x)=3(x-9)^2+4# is in vertex form, which is #f(x)=a(x-h)^2+k#, where #h=9, and k=4#. The vertex is #(h, k)#, which is #(9, 4)#. Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 3034 views around the world You can reuse this answer Creative Commons License