Question

How do you find the vertex of `f(x)= -x^2-3x-6`?

Answer 1

Vertex of`f(x) = - x^2 - 3x - 6`

Explanation:

x of vertex:

`x = (-b/(2a)) = 3/-2 = - 3/2`

y of vertex:

`y = f(-3/2) = - (9/4) + 9/2 - 6 = 9/4 - 6 = - 15/4`