How do you find the vertex of h(x) + 3/16x^2 - 5/8x - 1/2?

1 Answer
Feb 28, 2016

x_("vertex")=5/3

I have left y_("vertex") for you to derive by substitution.

Explanation:

Quick method: Find x_("vertex") then substitute it back into the original equation to find y_("vertex")

Given:" "3/16 x^2 -5/8 x-1/2 ............................(1)

'~~~~~~~~~~~~ For reference: ~~~~~~~~~~~~~~~~~
color(brown)(3/16 xxk =5/8) -> color(green)(k=5/8xx16/3= 10/3)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Write equation (1) as:

3/16(x^2color(green)(-10/3)x)-1/2

color(blue)(x_("vertex")= (-1/2)xx(-10/3) =+ 10/6 = +5/3 = 1.6667)

Tony B