Question

How do you find the vertex of the qraph `f(x)=7 (x-3)^2 -4`?

Answer 1

`"vertex at " (3,-4)`

Explanation:

The equation of a parabola in `color(blue)"vertex form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))`
where (h ,k) are the coordinates of the vertex.

`f(x)=7(x-3)^2-4" is in this form"`

by comparison h = 3 and k = - 4

`rArr"vertex " =(3,-4)`
graph{7(x-3)^2-4 [-10, 10, -5, 5]}