Question

How do you find the x and y intercepts for `x-2y=4`?

Answer 1

Intercepts are `(0, -2)` and `(4, 0)`

Explanation:

Given:

`x - 2y = 4`

The intercept with the `x` axis can be found by setting `y = 0` - effectively "covering up" the `-2y` term - to get:

`x = 4`

hence the `x` intercept is at `(4, 0)`

The intercept with the `y` axis can be found by setting `x = 0` or covering up the `x` term to get:

`-2y = 4`

Then dividing both sides by `-2` we find:

`y = -2`

So the `y` intercept is at `(0, -2)`

graph{(x-2y-4)((x-4)^2+y^2-0.01)(x^2+(y+2)^2-0.01) = 0 [-8.29, 11.71, -5.08, 4.92]}