How do you find the x coordinates of all points of inflection, final all discontinuities, and find the open intervals of concavity for #f(x)=x^4-8x^3#?
1 Answer
points of inflection at
concave up for
concave down for
Explanation:
You need the second derivative for concavity/inflection points
#f'(x)=4x^3- 24x^2#
#f^('')(x) = 12 x^2 - 48x#
#= 12 x(x-4)#
#f^('')(x)= 0# at#x =0# and#x=4#
Make a sign chart. To the left of