How do you find the zero of $f (x) = 3 x + 1$ $f(x)=3x+1$ ?

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Answer 1 · 2016-11-13T07:50:22

$x = - \frac{1}{3}$ $x=-1/3$

The zero(s) of a function $f (x)$ $f(x)$ are found when you set the function equivalent to 0.

$f (x) = 3 x + 1$ $f(x)=3x+1$
$0 = 3 x + 1$ $0=3x+1$
$- 1 = 3 x$ $-1=3x$
$- \frac{1}{3} = x$ $-1/3=x$

How do you find the zero of f(x)=3x+1f(x)=3x+1?