How do you find the zero of $f (x) = 4 x - 12$ $f(x)=4x-12$ ?

Question

7147 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-28T15:18:15

Solve the equation for $x$ $x$ , when $f (x) = 0$ $f(x)=0$
Then, $x = 3$ $x=3$ .

I assume you mean to find the solution/root (radical) $x$ $x$ , when $f (x) = 0$ $f(x)=0$ .

Then, this is simple.
Just set $f (x)$ $f(x)$ to 0 and solve the equation for $x$ $x$ :

$f (x) = 4 x - 12 = 0$ $f(x) = 4x - 12 = 0$

First we can add 12 on both sides of the equality:

$4 x - 12 + 12 = 0 + 12$ $4x - 12 +12 = 0+12$
which becomes
$4 x = 12$ $4x = 12$

We can now divide both sides of the equality by 4:
$\frac{4 x}{4} = \frac{12}{4}$ $(4x)/4 = (12)/4$
and we have
$x = 3$ $x = 3$

The "zero", or the solution for $f (x) = 0$ $f(x)=0$ is $x = 3$ $x=3$ .
Q.E.D.

How do you find the zero of f(x)=4x-12f(x)=4x−12f(x)=4x-12?