Question

How do you find the zeroes for `f(x) = x^2 + x - 3`?

Answer 1

f(x) = x^2 + x - 3 = 0

`D = d^2 = b^2 - 4ac = 1 + 12 = 13 -> d = +-sqr13`

`x = -b/(2a) +-d/(2a) = -1/2 +- (sqrt13)/2`