How do you find the zeroes of $P (x) = x^{6} - 729$ $P(x)=x^6-729$ ?

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Answer 1 · 2015-07-02T13:45:30

You may not see it right away, but $729 = 3^{6}$ $729=3^6$
(I recommend you allways look for something like this)

Since the exponent (6) is even it is also possible that $729 = {(- 3)}^{6}$ $729=(-3)^6$

So the question turns into:

$x^{6} = 3^{6} or x^{6} = {(- 3)}^{6} \to x = 3 or x = - 3$ $x^6=3^6orx^6=(-3)^6->x=3orx=-3$

How do you find the zeroes of P(x)=x6−729P(x)=x^6-729?