How do you find the zeros by rewriting the function y=x^2+16x+64 in intercept form?

1 Answer
Aug 27, 2017

y=(x+8)^2

Explanation:

We write the function as y=f(x) and factorize f(x) to find intercepts on x-axis. If f(x)=a(x-alpha)(x-beta), the zeros of f(x) are alpha and beta and intercepts are alpha and beta and y=a(x-alpha)(x-beta) is the equation in intercept form.

Here we have y=x^2+16x+64=(x+8)^2

Hence, we have just one intercept x=-8

graph{(x+8)^2 [-16.42, 3.58, -4.08, 5.92]}