Question

How do you find the zeros of `3x^2-10x+3=0`?

Answer 1

`x=1/3,x=3`

Explanation:

`"factorise the quadratic by 'splitting' the x-term"`

`rArr3x^2-10x+3=0`

`rArr3x^2-9x-x+3=0`

`rArr3x(x-3)-1(x-3)=0`

`rArr(x-3)(3x-1)=0`

`rArrx=3,x=1/3" are the zeros"`

Answer 2

Zeros are `x=3 and x=1/3`

Explanation:

`3x^2-10x+3=0 or 3x^2-9x-x+3=0 or 3x(x-3)-1(x-3)=0` or

`(x-3)(3x-1)= 0 :.` either

`x-3=0 :. x=3 or 3x-1=0 :. 3x=1 :. x=1/3`

Zeros are `x=3 and x=1/3` [Ans]