How do you find the zeros of #f(x)=5x^2-25x+30#?
2 Answers
See a solution process below:
Explanation:
We can factor this function as:
To find the zeros we can solve each term on the right side of the function for
Solution 1:
Solution 2:
The Solutions Are:
Explanation:
#"to calculate the zeros set "f(x)=0#
#rArr5x^2-25x+30=0larrcolor(blue)"factorise to solve"#
#rArr5(x^2-5x+6)=0#
#"the factors of + 6 which sum to - 5 are -2 and - 3"#
#rArr5(x-2)(x-3)=0#
#"equate each factor to zero and solve for x"#
#x-2=0rArrx=2#
#x-3=0rArrx=3#
#"the zeros are "x=2,x=3#
graph{(y-x^2+5x-6)((x-2)^2+y^2-0.07)((x-3)^2+y^2-0.07)=0 [-10, 10, -5, 5]}