How do you find the zeros of the function f(x)= x^2-2x-4f(x)=x2−2x−4?

1 Answer
Daniel L.
May 5, 2015

The zeros of this function are x_1=1-sqrt(5)x1=1−√5 and x_2=1+sqrt(5)x2=1+√5

To find the zeros of a quadratic function you first have to calculate Delta. In this case it is Delta = (-2)^2-4*1*(-4) = 20
Delta > 0 so function has 2 real zeros which can be calculated using:

x_1=(-b-sqrt(Delta))/(2a) and x_2 = (-b+sqrt(Delta))/(2a)

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