How do you find the zeros of the polynomial function with equation $f(x) = (x + 4)(2x – 1)(x – 7)$ ?

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Answer 1 · 2016-02-22T16:17:10

$4$ , $1/2$ and $7$ are zeros of $f(x)=(x+4)(2x–1)(x–7)$ .

Zeros of the polynomial function $f(x)=(x+4)(2x–1)(x–7)$ , are those values of $x$ for which value of $f(x)$ becomes $0$ .

As $f(x)$ is a multiple of three linear functions $(x+4)$ , $(2x–1)$ , and $(x–7)$ , $f(x)$ if any of these three linear function is equal to zero.

Hence, zeros of $f(x)$ are given by $(x+4)=0$ , $(2x–1)=0$ , and $(x–7)=0$ , i.e. for $x=-4$ , $x=1/2$ and $x=7$ .

Hence, $4$ , $1/2$ and $7$ are zeros of $f(x)=(x+4)(2x–1)(x–7)$ .

How do you find the zeros of the polynomial function with equation f(x) = (x + 4)(2x – 1)(x – 7) f(x) = (x + 4)(2x – 1)(x – 7)?