Question

How do you find the zeros of `y=3x^2+2x`?

Answer 1

`x=0` or `x=-2/3`

Explanation:

`y= 3x^2+2x`

`= x(3x+2)`

The zeros of `y` are those values of `x` such that `y=0`

I.e. where `x(3x+2) =0`

`:. x=0` or `3x+2=0`

Hence: `x=0` or `x=-2/3`