How do you find the zeros of $y = (x + 2) (x - 4) (x + 1)$ $y = (x + 2)(x − 4)(x + 1)$ ?

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Answer 1 · 2016-06-24T22:19:30

$x = - 2$ $x=-2$ , $x = 4$ $x=4$ and $x = - 1$ $x=-1$

A product of three numbers is zero if and only if at least one of the numbers is zero.

In our example:

$y = (x + 2) (x - 4) (x + 1)$ $y = (x+2)(x-4)(x+1)$

So $(x + 2) (x - 4) (x + 1) = 0$ $(x+2)(x-4)(x+1)=0$ if and only if at least one of the following holds:

So the three zeros are: $x = - 2$ $x=-2$ , $x = 4$ $x=4$ and $x = - 1$ $x=-1$

How do you find the zeros of y=(x+2)(x−4)(x+1)y = (x + 2)(x − 4)(x + 1)?