How do you find the zeros of $y = (x + 4) (x - 5) (x - 6)$ $y=(x+4)(x-5)(x-6)$ ?

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Answer 1 · 2017-02-03T08:47:08

See explanation.

The given formula is a product of 3 expressions, so it is equal to zero if and only if any of those expressions is zero:

$(x + 4) (x - 5) (x - 6) = 0 \Leftrightarrow$ $(x+4)(x-5)(x-6)=0 iff$

$x + 4 = 0 \lor x - 5 = 0 \lor x - 6 = 0 \Leftrightarrow$ $x+4=0 vv x-5=0 vv x-6=0 iff$

$x = - 4 \lor x = 5 \lor x = 6$ $x=-4 vv x=5 vv x=6$

Answer:

This function has 3 zeros:

$x_{1} = - 4$ $x_1=-4$ , $x_{2} = 5$ $x_2=5$ and $x_{3} = 6$ $x_3=6$

How do you find the zeros of y=(x+4)(x−5)(x−6)y=(x+4)(x-5)(x-6)?